Lines Matching +full:2 +full:k
14 __attribute__((nonnull(2,3,4)))
50 __attribute__((nonnull(2,3,4,5)))
119 * 2:1 balanced merges. Given two pending sublists of size 2^k, they are
120 * merged to a size-2^(k+1) list as soon as we have 2^k following elements.
122 * Thus, it will avoid cache thrashing as long as 3*2^k elements can
131 * Each time we increment "count", we set one bit (bit k) and clear
132 * bits k-1 .. 0. Each time this happens (except the very first time
133 * for each bit, when count increments to 2^k), we merge two lists of
134 * size 2^k into one list of size 2^(k+1).
137 * 2^k, which is when we have 2^k elements pending in smaller lists,
138 * so it's safe to merge away two lists of size 2^k.
140 * After this happens twice, we have created two lists of size 2^(k+1),
141 * which will be merged into a list of size 2^(k+2) before we create
142 * a third list of size 2^(k+1), so there are never more than two pending.
144 * The number of pending lists of size 2^k is determined by the
145 * state of bit k of "count" plus two extra pieces of information:
147 * - The state of bit k-1 (when k == 0, consider bit -1 always set), and
149 * is count >= 2^(k+1)).
153 * 0: 00x: 0 pending of size 2^k; x pending of sizes < 2^k
154 * 1: 01x: 0 pending of size 2^k; 2^(k-1) + x pending of sizes < 2^k
155 * 2: x10x: 0 pending of size 2^k; 2^k + x pending of sizes < 2^k
156 * 3: x11x: 1 pending of size 2^k; 2^(k-1) + x pending of sizes < 2^k
157 * 4: y00x: 1 pending of size 2^k; 2^k + x pending of sizes < 2^k
158 * 5: y01x: 2 pending of size 2^k; 2^(k-1) + x pending of sizes < 2^k
159 * (merge and loop back to state 2)
161 * We gain lists of size 2^k in the 2->3 and 4->5 transitions (because
162 * bit k-1 is set while the more significant bits are non-zero) and
163 * merge them away in the 5->2 transition. Note in particular that just
164 * before the 5->2 transition, all lower-order bits are 11 (state 3),
168 * lists, from smallest to largest. If you work through cases 2 to
170 * of size 2^k varies from 2^(k-1) (cases 3 and 5 when x == 0) to
171 * 2^(k+1) - 1 (second merge of case 5 when x == 2^(k-1) - 1).
173 __attribute__((nonnull(2,3)))
197 * That ensures each later final merge will be at worst 2:1. in list_sort()